Fluid Dynamics and the Navier-Stokes Equations

The subject of fluid dynamics deals with the motion of liquids and gases, which when studied macroscopically, appear to be continuous in structure. All the variables are considered to be continuous functions of the spatial coordinates and time. The Navier-Stokes equations are a set of nonlinear partial differential equations that describe the flow of fluids. For example: they model weather or the movement of air in the atmosphere, ocean currents, water flow in a pipe, as well as many other fluid flow phenomena. The Navier-Stokes equations for irrotational flow (when x u = 0) are:
Navier-Stokes Eq.








(3)
where u = velocity vector field, = thermodynamic internal energy, p = pressure, T = temperature, = density,
= viscosity, KH = heat conduction coefficient, and F = external force per unit mass.

The Navier-Stokes equations are time-dependent and consist of a continuity equation for conservation of mass, three conservation of momentum equations and a conservation of energy equation. There are four independent variables in the equation - the x, y, and z spatial coordinates, and the time t; six dependent variables - the pressure p, density , temperature T, and three components of the velocity vector u. Together with the equation of state such as the ideal gas law - p V = n R T, the six equations are just enough to determine the six dependent variables. In general, all of the dependent variables are functions of all four independent variables. Usually, the Navier-Stokes equations are too complicated to be solved in a closed form. However, in some special cases the equations can be simplified and may admit analytical solutions. The steady flow in a pipe is a very simple solvable case. Since the left-hand side of Eq.(2) vanishes for steady flow, and there is no external force, it can be written in cylinderical coordinates as:

0 = - dp / dz + (1/r) d (r d v / dr) / dr ---------- (4)

where v denotes the velocity field in the z direction as shown in Figure 02. For a constant pressure drop (per unit length)
d p / dz is a negative constant, the solution becomes:

v (r) = vm ( 1 - r2 / R2 ) ---------- (5)

where vm = (R2 / 4 ) (- dp / dz) ---------- (6)
is the velocity at the centre, and R is the radius of the pipe. The boundary conditions are v = vm at r = 0 and v = 0 at r = R.